SMA Physics

SENIOR SECONDARY PHYSICS LABORATORY

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📘 CBSE / State Board Senior Secondary Curriculum

Physics Practical Reference & Laboratory Manual

Complete academic laboratory manuals accompanying the SMA Physics Virtual Physics Simulations. Each experiment features detailed theory with mathematical formulation, apparatus specifications, standardized procedures, tabular observations, critical precautions, and viva-voce preparation.

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EXPERIMENT 01 • Class XI Physics

Vernier Callipers: Dimensions & Volume Lab

🎯 Aim of the Experiment

To determine the internal diameter, external diameter, and depth of a hollow cylindrical calorimeter/beaker and calculate its internal volume using Vernier Callipers.

🧰 Apparatus & Materials Required

Vernier Callipers, cylindrical calorimeter/beaker, spherical bob, magnifying lens.

📐 Governing Theory & Formulae

A Vernier Calliper operates on the principle that $N$ divisions of the sliding Vernier Scale coincide with $(N - 1)$ divisions of the stationary Main Scale.

Least Count (LC):
$$LC = 1\text{ MSD} - 1\text{ VSD} = \frac{1\text{ MSD}}{N} = \frac{1\text{ mm}}{10} = 0.1\text{ mm} = 0.01\text{ cm}$$
Total Reading (TR):
$$TR = MSR + (VSR \times LC) - (\pm e)$$ where $MSR$ is Main Scale Reading, $VSR$ is Vernier Scale Coincidence, and $e$ is zero error.

Internal Volume of Cylinder ($V$):
$$V = \frac{\pi D_i^2}{4} \times d$$ where $D_i$ is mean internal diameter and $d$ is depth.
📝 Step-by-Step Procedure
  1. Examine the Vernier Callipers to determine its Least Count ($0.01\text{ cm}$).
  2. Bring jaws $A$ and $B$ into contact to inspect zero error. If zero of Vernier scale lies to the right of main scale zero, error is positive; if to the left, error is negative.
  3. To measure external diameter ($D_e$), place the cylinder between external jaws $A$ and $B$ and tighten gently using the clamp screw.
  4. Record the main scale reading immediately preceding the vernier zero mark.
  5. Observe which vernier division aligns exactly with any main scale graduation using a magnifying lens.
  6. Repeat readings at 3 different cross-sections at mutually perpendicular directions to eliminate ellipticity.
  7. To measure internal diameter ($D_i$), place upper jaws $C$ and $D$ inside the hollow cylinder and expand until snug.
  8. To measure depth ($d$), insert the thin metallic depth strip vertically until it touches the cylinder base while the calliper edge rests flat on the rim.
  9. Compute mean internal diameter and depth, then calculate internal volume.
📊 Observation Tables & Sample Readings
Dimension Obs. No. MSR ($cm$) VSR ($div$) VSR $\times$ LC ($cm$) Total Reading ($cm$) Corrected Reading ($cm$) Mean Value ($cm$)
Internal Diameter ($D_i$)14.250.054.254.254.25 cm
24.260.064.264.26
34.240.044.244.24
Depth ($d$)18.530.038.538.538.54 cm
28.550.058.558.55
38.540.048.548.54
⚠️ Precautions & Sources of Error
  • Do not apply excessive pressure on the jaws; turn the adjusting screw smoothly to avoid bending or deforming the jaws.
  • Always record observations at three mutually perpendicular diameters to account for non-uniform circular cross-sections.
  • View the vernier alignment directly perpendicular to the scale to avoid parallax error.
  • Always apply zero correction with proper algebraic sign ($TR = \text{Observed} - \text{Zero Error}$).
💬 Practical Viva-Voce Questions
Q1: What is the principle of a Vernier?
A: The vernier principle relies on making $N$ vernier scale divisions equal in length to $(N-1)$ main scale divisions, allowing measurement down to a fraction of a main scale division.
Q2: What is the difference between positive and negative zero error?
A: In positive zero error, vernier zero lies to the right of main scale zero (measured reading is greater than actual, so zero correction is subtracted). In negative zero error, vernier zero lies to the left (measured reading is smaller, so correction is added).
Q3: Why are the tips of the external jaws slightly curved?
A: Curved edges provide narrow contact surfaces for measuring cylindrical or spherical objects accurately along their true diametrical line without pinching.
EXPERIMENT 02 • Class XI Physics

Screw Gauge: Wire Diameter & Sheet Thickness Measurement

🎯 Aim of the Experiment

To measure the diameter of a given wire and thickness of a given sheet using a micrometer screw gauge and calculate its cross-sectional area and volume.

🧰 Apparatus & Materials Required

Screw gauge ($0-25\text{ mm}$, $LC = 0.001\text{ cm}$), thin copper/nichrome wire, metallic sheet, half-meter rule.

📐 Governing Theory & Formulae

The micrometer screw gauge is based on the principle of the screw: linear advancement along the axis is directly proportional to circular rotation of the thimble head.

Pitch of the Screw:
$$\text{Pitch} = \frac{\text{Distance moved on Linear Pitch Scale}}{\text{Number of complete rotations}} = 1\text{ mm}$$
Least Count (LC):
$$LC = \frac{\text{Pitch}}{\text{Total Circular Head Divisions}} = \frac{1\text{ mm}}{100} = 0.01\text{ mm} = 0.001\text{ cm}$$
Cross-Sectional Area ($A$) & Volume ($V$):
$$A = \frac{\pi D^2}{4}, \quad V = A \times L = \frac{\pi D^2 L}{4}$$
📝 Step-by-Step Procedure
  1. Determine pitch by rotating the thimble 5 complete turns and observing linear progression along the sleeve scale.
  2. Determine least count ($LC = 0.001\text{ cm}$).
  3. Rotate the ratchet stop until anvil and spindle faces meet. Inspect zero error against reference datum line.
  4. Place the wire between anvil and spindle. Turn the ratchet head until it slips with 3 distinct audible clicks.
  5. Note the Pitch Scale Reading (PSR) and the Circular Scale Division (CSR) aligned with the reference line.
  6. Repeat measurements at 5 equidistant locations along the wire, taking two perpendicular diameters at each spot.
  7. Measure total length $L$ with a meter scale and compute wire volume.
📊 Observation Tables & Sample Readings
Position Direction PSR ($mm$) HSR ($div$) HSR $\times$ LC ($mm$) Observed $D$ ($mm$) Corrected $D$ ($mm$) Mean Diameter ($mm$)
Position 1Horizontal0.0420.420.420.420.423 mm (0.0423 cm)
Vertical0.0430.430.430.43
Position 2Horizontal0.0420.420.420.42
Vertical0.0420.420.420.42
⚠️ Precautions & Sources of Error
  • Always advance and tighten the screw using the ratchet stop, never the knurled thimble directly, to avoid crushing the specimen or stripping screw threads.
  • Turn the screw only in one direction during measurement to prevent backlash error caused by mechanical thread wear.
  • Clean the planar faces of both anvil and spindle before zero error inspection.
💬 Practical Viva-Voce Questions
Q1: What is backlash error in a screw gauge?
A: Backlash error is the mechanical play between screw threads and internal nut caused by wear and tear. When the direction of rotation is reversed, the screw rotates through a small angle without translating linearly. It is eliminated by advancing the screw always in the same direction.
Q2: Why is a ratchet stop provided on a screw gauge?
A: The ratchet contains a spring-loaded clutch mechanism that slips when a predetermined gentle pressure is reached, ensuring uniform contact pressure across all trials regardless of user strength.
EXPERIMENT 03 • Class XI Physics

Spherometer: Radius of Curvature of Spherical Surfaces

🎯 Aim of the Experiment

To determine the radius of curvature of a given spherical surface (convex watch glass/concave mirror) using a spherometer.

🧰 Apparatus & Materials Required

Spherometer, plane glass plate, spherical watch glass/convex mirror, sheet of white paper, sharp pencil, millimeter rule.

📐 Governing Theory & Formulae

A spherometer measures the sagitta (height of bulge or depth of depression $h$) of a spherical cap supported on an equilateral triangular base of leg distance $l$.

Radius of Curvature ($R$):
$$R = \frac{l^2}{6h} + \frac{h}{2}$$ where $l = \frac{l_1 + l_2 + l_3}{3}$ is the mean distance between the outer three prongs, and $h$ is the sagitta height measured by the central micrometer screw.
📝 Step-by-Step Procedure
  1. Press the spherometer legs gently onto paper to produce 3 prong indentations forming an equilateral triangle. Measure distances $l_1, l_2, l_3$ and compute mean $l$.
  2. Place the spherometer on a flat plane glass slab. Rotate central screw downwards until its tip just touches the glass without lifting the three outer legs.
  3. Record the plane zero vertical scale and circular head readings.
  4. Place the spherometer centrally on the convex/concave spherical surface.
  5. Turn the screw until the central tip touches the apex of the spherical surface.
  6. Calculate sagitta $h = |\text{Surface Reading} - \text{Plane Zero Reading}|$.
  7. Substitute $l$ and $h$ into formula to calculate radius of curvature $R$.
📊 Observation Tables & Sample Readings
Prong Distance $l_1$ ($cm$) $l_2$ ($cm$) $l_3$ ($cm$) Mean $l$ ($cm$) Pitch ($mm$) LC ($mm$)
Values4.104.124.114.111.00.01
Trial Plane Zero Reading ($mm$) Spherical Surface Reading ($mm$) Sagitta $h$ ($mm$) Sagitta $h$ ($cm$) Calculated $R$ ($cm$)
10.001.451.450.14519.46
20.001.461.460.14619.33
30.001.451.450.14519.46
⚠️ Precautions & Sources of Error
  • Ensure the central screw does not press so hard that the outer legs lift off the surface. Use a thin paper strip under each leg to test contact.
  • Rotate the micrometer screw strictly in one direction to eliminate backlash error.
💬 Practical Viva-Voce Questions
Q1: What is meant by sagitta?
A: Sagitta is the perpendicular height of the central apex of a spherical cap above the plane passing through the three base points of the spherometer legs.
Q2: Why does $R = \frac{l^2}{6h} + \frac{h}{2}$ contain $h/2$?
A: Derived from geometry of intersecting chords in a circle: $h(2R - h) = r^2$. Since base radius $r = l / \sqrt{3}$, $2Rh - h^2 = l^2/3$, giving $R = \frac{l^2}{6h} + \frac{h}{2}$.
EXPERIMENT 04 • Class XI Physics

Volume of Irregular Lamina: Screw Gauge & Graph Paper

🎯 Aim of the Experiment

To determine the volume of a given irregular thin lamina using millimeter graph paper and a micrometer screw gauge.

🧰 Apparatus & Materials Required

Irregular lamina (cardboard/metallic plate), $1\text{ mm}$ graph sheet, sharp pencil, micrometer screw gauge.

📐 Governing Theory & Formulae

Volume of any regular or irregular prismatic sheet is the product of its surface area $A$ and uniform thickness $t$.

Volume ($V$):
$$V = \text{Surface Area } (A) \times \text{Thickness } (t)$$
Area via Millimeter Grid Squares:
$$A = \left(N_1 + \frac{1}{2} N_2\right) \times 1\text{ mm}^2$$ where $N_1$ is number of complete enclosed $1\text{ mm}^2$ squares, and $N_2$ is number of squares more than or equal to half enclosed within the boundary contour.
📝 Step-by-Step Procedure
  1. Place the irregular lamina flat on a sheet of millimeter graph paper.
  2. Trace its perimeter boundary carefully using a very sharp pencil held perpendicularly.
  3. Count all complete squares enclosed within the boundary ($N_1$).
  4. Count all boundary squares that have half or more than half their area inside the contour ($N_2$). Ignore squares with less than half area inside.
  5. Compute total surface area $A$.
  6. Measure thickness $t$ at 5 widely separated locations using a calibrated screw gauge with zero error correction applied.
  7. Calculate total volume $V = A \times t$.
📊 Observation Tables & Sample Readings
Trial Full Squares ($N_1$) Half/More Squares ($N_2$) Total Area ($mm^2$) Total Area ($cm^2$)
11420116147814.78
Spot PSR ($mm$) HSR ($div$) Observed $t$ ($mm$) Corrected $t$ ($mm$) Mean Thickness ($cm$) Calculated Volume ($cm^3$)
11.0241.241.240.124 cm1.833 cm³
21.0251.251.25
31.0231.231.23
⚠️ Precautions & Sources of Error
  • Use an extremely sharp 2H pencil so that boundary line thickness does not introduce area bias.
  • Ensure the lamina is perfectly flat without warping or bent corners.
💬 Practical Viva-Voce Questions
Q1: Why cannot Archimedes liquid immersion be used for very thin sheets?
A: Thin laminae have negligible volume compared to liquid surface tension meniscus uncertainties in measuring cylinders, resulting in high fractional measurement error.
EXPERIMENT 05 • Class XI Physics

Physical Beam Balance: Determination of Mass

🎯 Aim of the Experiment

To determine the mass of a given body using a physical beam balance by the method of resting point oscillations.

🧰 Apparatus & Materials Required

Physical balance, analytical weight box with forceps, fractional milligram weights, spirit level, plumb line, unknown body.

📐 Governing Theory & Formulae

A beam balance operates on the principle of moments: equilibrium occurs when clockwise moment equals counter-clockwise moment about the central fulcrum.

$$M_{\text{body}} \times g \times l_1 = M_{\text{weights}} \times g \times l_2$$ For equal arms ($l_1 = l_2$), $M_{\text{body}} = M_{\text{weights}}$.

Resting Point (RP) by Oscillations:
$$RP = \frac{L_1 + 2L_2 + L_3}{4}$$ where $L_1, L_3$ are turning points on left and $L_2$ is turning point on right.
$$\text{Mass Correction } \Delta M = \frac{ZRP - RP}{\text{Sensitivity}} \times 10\text{ mg}$$
📝 Step-by-Step Procedure
  1. Level the balance using foot screws until the plumb line aligns with the pointed cone index.
  2. Release the beam arresting knob and determine the Zero Resting Point (ZRP) by recording three consecutive turning points of the pointer on the graduated scale.
  3. Arrest the beam. Place the unknown body in the left pan.
  4. Place standard gram weights in the right pan using forceps. Always arrest the beam before changing weights!
  5. Add fractional milligram weights until pointer swings symmetrically across scale.
  6. Determine resting point with weights ($RP$). Calculate exact mass with oscillation correction.
📊 Observation Tables & Sample Readings
Condition Turning Point 1 ($L_1$) Turning Point 2 ($L_2$) Turning Point 3 ($L_3$) Calculated RP
Zero Load (ZRP)9.211.49.410.35
With Body + 24.35 g8.811.89.010.35
⚠️ Precautions & Sources of Error
  • Always arrest the beam completely before adding or removing weights to protect delicate agate knife-edges.
  • Handle weights strictly with clean bone-tipped forceps; finger oil/sweat alters fractional milligram accuracy.
  • Keep glass doors shut during oscillation readings to eliminate air draft currents.
💬 Practical Viva-Voce Questions
Q1: Why are knife-edges and bearing planes made of agate?
A: Agate is extremely hard, non-corrosive, and non-magnetic, ensuring knife-edges retain ultra-sharp line contact without wearing down.
EXPERIMENT 06 • Class XI Physics

Parallelogram Law of Vectors: Gravesand's Apparatus

🎯 Aim of the Experiment

To determine the weight of a given body using the Parallelogram Law of Vectors on Gravesand's apparatus.

🧰 Apparatus & Materials Required

Gravesand's vertical drawing board, 2 low-friction pulleys, slotted weights with hangers, white paper, drawing pins, mirror strip, thread, unknown weight.

📐 Governing Theory & Formulae

If two concurrent forces $\vec{P}$ and $\vec{Q}$ acting at a point are represented in magnitude and direction by adjacent sides of a parallelogram, their resultant $\vec{R}$ is represented by the diagonal passing through their common junction.

$$R = \sqrt{P^2 + Q^2 + 2PQ \cos\theta}$$ In static equilibrium with unknown suspended weight $W$ acting vertically downward:
$$\vec{P} + \vec{Q} + \vec{W} = 0 \implies W = R$$
📝 Step-by-Step Procedure
  1. Fix drawing paper to vertical board. Ensure pulleys move without friction.
  2. Pass thread over pulleys. Suspend known weights $P$ and $Q$ on sides and unknown weight $W$ from central junction knot $O$.
  3. Adjust weights until knot $O$ rests near center of board without touching paper.
  4. Mark directions of all three threads using plane mirror parallax method (align thread with its reflection).
  5. Choose suitable vector scale ($1\text{ cm} = 50\text{ g-wt}$) and draw vectors $\vec{OA} = P$ and $\vec{OB} = Q$.
  6. Complete parallelogram $OACB$ and measure length of diagonal $OC$.
  7. Calculate unknown weight $W = OC \times \text{Scale}$. Compare with spring balance reading.
📊 Observation Tables & Sample Readings
Trial Weight $P$ ($g$-wt) Weight $Q$ ($g$-wt) Included Angle $\theta$ Diagonal Length $OC$ ($cm$) Resultant $R$ ($g$-wt) True Weight $W$ ($g$-wt) Error (%)
115015072°4.85242.5240+1.0%
220015065°5.88294.0295-0.3%
⚠️ Precautions & Sources of Error
  • Pulleys must be frictionless and oiled.
  • Threads must remain parallel to drawing board without rubbing against paper.
💬 Practical Viva-Voce Questions
Q1: Why is a mirror strip used to mark thread lines?
A: Placing a mirror behind thread and positioning eye such that thread covers its own reflection completely eliminates optical parallax error.
EXPERIMENT 07 • Class XI Physics

Simple Pendulum: L–T² Graph & Determination of 'g'

🎯 Aim of the Experiment

To study the variation of time period $T$ with length $L$ of a simple pendulum, plot an $L-T^2$ graph, determine acceleration due to gravity $g$, and find length of a second's pendulum.

🧰 Apparatus & Materials Required

Heavy metallic spherical bob with hook, light inextensible cord, split cork, rigid retort stand, vernier callipers, meter scale, precision digital stopwatch.

📐 Governing Theory & Formulae

For small angular displacement ($\theta \le 4^\circ$), the simple pendulum executes Simple Harmonic Motion (SHM).

$$T = 2\pi \sqrt{\frac{L}{g}} \implies T^2 = \left(\frac{4\pi^2}{g}\right) L$$ $$\text{Slope of } L-T^2 \text{ graph } S = \frac{T^2}{L} \implies g = \frac{4\pi^2}{\text{Slope}} = 4\pi^2 \left(\frac{L}{T^2}\right)$$
Second's Pendulum ($T = 2\text{ s}$):
$$L_{\text{sec}} = \frac{g \times (2)^2}{4\pi^2} = \frac{g}{\pi^2} \approx 99.3\text{ cm}$$
📝 Step-by-Step Procedure
  1. Measure bob diameter with Vernier Callipers to get radius $r$.
  2. Clamp cord firmly between two halves of split cork. Adjust effective length $L = l + r + e$ to $60\text{ cm}$.
  3. Pull bob aside by small angle ($< 4^\circ$) and release without imparting spin.
  4. Start stopwatch as bob crosses central equilibrium line. Measure time for 20 complete oscillations twice.
  5. Repeat for lengths $70, 80, 90, 100, 110\text{ cm}$.
  6. Compute period $T = t / 20$, $T^2$, and $L/T^2$. Plot $L$ vs $T^2$ linear graph and deduce $g$.
📊 Observation Tables & Sample Readings
Length $L$ ($cm$) Time for 20 osc $t_1$ ($s$) Time for 20 osc $t_2$ ($s$) Mean Time ($s$) Period $T$ ($s$) $T^2$ ($s^2$) $L / T^2$ ($cm/s^2$)
60.031.131.031.051.5532.41024.89
80.035.935.835.851.7933.21324.90
100.040.140.240.152.0084.03024.81
⚠️ Precautions & Sources of Error
  • Angular amplitude must remain under $4^\circ$ so that $\sin\theta \approx \theta$.
  • Oscillations must be planar without conical or spinning motion.
💬 Practical Viva-Voce Questions
Q1: What is a second's pendulum?
A: A pendulum whose period of oscillation is exactly 2 seconds (it takes 1 second to swing from one extreme to the other). Its length at sea level is approximately 99.3 cm.
EXPERIMENT 08 • Class XI Physics

Limiting Friction vs Normal Reaction (F–R Graph)

🎯 Aim of the Experiment

To study the relationship between the force of limiting friction and normal reaction, and determine the coefficient of static friction $\mu_s$ between a wooden block and a horizontal table.

🧰 Apparatus & Materials Required

Horizontal wooden bench with frictionless pulley, wooden block with hook, pan, slotted weights ($50\text{ g}, 100\text{ g}$), spring balance, thread.

📐 Governing Theory & Formulae

The maximum opposing frictional force before a body begins to slide is the limiting friction $F_s$, directly proportional to normal reaction $R$.

$$F_s = \mu_s R$$ where $\mu_s$ is the coefficient of static friction.
$$R = (M_{\text{block}} + m_{\text{weights on block}}) g, \quad F = (m_{\text{pan}} + m_{\text{weights on pan}}) g$$ $$\mu_s = \frac{F}{R} = \text{Slope of } F-R \text{ graph}$$
📝 Step-by-Step Procedure
  1. Weigh the wooden block and scale pan using a spring balance.
  2. Place block on clean horizontal bench. Attach thread passing horizontally over pulley to suspended pan.
  3. Add small weights to pan and tap bench gently until block just begins to slide. Note total pan mass.
  4. Add $50\text{ g}, 100\text{ g}, 150\text{ g}, 200\text{ g}$ atop the block to increase normal reaction $R$.
  5. Record corresponding limiting pulling force $F$. Plot $F$ vs $R$ and determine slope $\mu_s$.
📊 Observation Tables & Sample Readings
Trial Weight on Block ($g$) Total Normal Reaction $R$ ($g$-wt) Weight in Pan ($g$) Limiting Friction $F$ ($g$-wt) $\mu_s = F / R$
1020062820.41
21003001031230.41
32004001451650.41
⚠️ Precautions & Sources of Error
  • The string connecting block to pulley must be strictly horizontal.
  • Always tap the bench gently to overcome initial contact stickiness.
💬 Practical Viva-Voce Questions
Q1: Why is static friction called a self-adjusting force?
A: It adjusts both its magnitude and direction to exactly oppose any applied force up to the threshold of limiting friction.
EXPERIMENT 09 • Class XI Physics

Inclined Plane: Downward Force vs sin θ Relationship

🎯 Aim of the Experiment

To study the downward force along an inclined plane acting on a roller due to gravity and verify its relationship with $\sin\theta$.

🧰 Apparatus & Materials Required

Inclined plane with protractor and pulley, heavy metallic roller, spring balance, weight pan, slotted weights, light cord.

📐 Governing Theory & Formulae

A mass $m$ placed on an incline tilted at angle $\theta$ experiences gravitational components:

$$W_{\parallel} = mg \sin\theta \quad (\text{downward along slope})$$ $$W_{\perp} = mg \cos\theta \quad (\text{normal reaction into slope})$$ A plot of $F_{\text{down}}$ versus $\sin\theta$ yields a straight line passing through origin with slope equal to $mg$.
📝 Step-by-Step Procedure
  1. Weigh roller and pan. Set inclined plane angle $\theta = 20^\circ$.
  2. Attach cord to roller, pass over top pulley, and attach to pan.
  3. Determine weight $W_1$ needed in pan for roller to move up with constant speed.
  4. Determine weight $W_2$ in pan when roller moves down with constant speed.
  5. Mean downward force $F = \frac{W_1 + W_2}{2}$ eliminates rolling friction.
  6. Repeat for $\theta = 30^\circ, 40^\circ, 45^\circ, 50^\circ$. Plot $F$ vs $\sin\theta$.
📊 Observation Tables & Sample Readings
Angle $\theta$ $\sin\theta$ $W_1$ (Moving Up, $g$-wt) $W_2$ (Moving Down, $g$-wt) Mean Force $F$ ($g$-wt) Theoretical $mg\sin\theta$
20°0.342185155170171
30°0.500265235250250
45°0.707370340355354
⚠️ Precautions & Sources of Error
  • Cord must be parallel to the plane surface.
  • Pulley must be frictionless and clean.
💬 Practical Viva-Voce Questions
Q1: Why do we take average of upward and downward moving weights?
A: Moving up: $T_1 = mg\sin\theta + f_r$. Moving down: $T_2 = mg\sin\theta - f_r$. The mean $(T_1 + T_2)/2 = mg\sin\theta$ cancels friction completely.
EXPERIMENT 10 • Class XII Physics

Ohm's Law: V–I Characteristic, Resistance & Resistivity

🎯 Aim of the Experiment

To determine resistance per unit length of a given wire by plotting a graph of potential difference versus current, and calculate specific resistance (resistivity) of its material.

🧰 Apparatus & Materials Required

Resistance wire (Constantan/Nichrome), DC power supply ($0-6\text{ V}$), DC ammeter ($0-1.5\text{ A}$), DC voltmeter ($0-3\text{ V}$), rheostat, plug key, connecting wires, screw gauge, meter scale.

📐 Governing Theory & Formulae

Ohm's Law: Electric current $I$ flowing through a conductor is directly proportional to potential difference $V$ across its ends, provided physical conditions (temperature, strain) remain constant.

$$V = I \cdot R \implies R = \frac{V}{I} = \text{Slope of } V-I \text{ graph}$$
Specific Resistance (Resistivity $\rho$):
$$\rho = R \frac{A}{L} = R \frac{\pi D^2}{4L} \quad (\Omega \cdot \text{m})$$
📝 Step-by-Step Procedure
  1. Clean wire terminals with sandpaper. Connect battery, key, rheostat, ammeter, and resistance wire in series.
  2. Connect voltmeter in parallel across the resistance wire.
  3. Insert key and adjust rheostat so that ammeter and voltmeter show measurable deflections.
  4. Record ammeter current $I$ and voltmeter voltage $V$.
  5. Shift rheostat slider to obtain 6 distinct sets of $V$ and $I$ values.
  6. Measure wire length with meter rule and diameter with screw gauge.
  7. Plot $V$ vs $I$ graph and compute slope $R$ and resistivity $\rho$.
📊 Observation Tables & Sample Readings
Obs. No. Ammeter Current $I$ ($A$) Voltmeter Voltage $V$ ($V$) Resistance $R = V / I$ ($\Omega$) Mean Resistance ($\Omega$)
10.201.005.005.01 Ω
20.402.015.02
30.603.005.00
40.804.025.02
⚠️ Precautions & Sources of Error
  • Keep the plug key open between readings to prevent Joule heating ($I^2Rt$), which increases resistance.
  • Connect voltmeter strictly in parallel and ammeter in series with correct polarity ($+$ to $+$).
💬 Practical Viva-Voce Questions
Q1: Why does Ohm's law fail if current flows continuously for long periods?
A: Continuous current heats the wire via Joule heating ($H = I^2Rt$). In metallic conductors, increased temperature increases lattice vibrations, increasing resistance and curving the V-I line.
EXPERIMENT 11 • Class XII Physics

Meter Bridge (Slide Wire Bridge): Unknown Resistance & Resistivity

🎯 Aim of the Experiment

To find the resistance of a given wire using a meter bridge and determine the specific resistance (resistivity) of its material.

🧰 Apparatus & Materials Required

Meter bridge ($100\text{ cm}$ slide wire), center-zero galvanometer, Leclanché/DC cell, resistance box ($1-100\,\Omega$), sliding jockey, unknown resistance wire, screw gauge, meter scale.

📐 Governing Theory & Formulae

The meter bridge is a practical laboratory realization of the Wheatstone bridge null deflection principle.

$$\frac{P}{Q} = \frac{R}{X} \implies \frac{\sigma l}{\sigma (100 - l)} = \frac{R}{X}$$ $$X = R \left(\frac{100 - l}{l}\right)$$
Specific Resistivity ($\rho$):
$$\rho = X \frac{\pi D^2}{4L}$$
📝 Step-by-Step Procedure
  1. Connect standard resistance box $R$ in left gap and unknown coil $X$ in right gap. Connect battery across end brass terminals $A$ and $C$, and galvanometer between central terminal $B$ and jockey.
  2. Test connection by touching jockey at $l=5\text{ cm}$ and $l=95\text{ cm}$; galvanometer needle must deflect in opposite directions.
  3. Take out suitable resistance $R$ from box ($2-6\,\Omega$). Slide jockey gently to locate null deflection point ($I_g = 0$).
  4. Record balancing length $l$ from zero end.
  5. Repeat for 5 different values of $R$ ensuring balance point remains between $35\text{ cm}$ and $65\text{ cm}$.
  6. Measure wire diameter with screw gauge and calculate resistivity $\rho$.
📊 Observation Tables & Sample Readings
Obs. No. Known Resistance $R$ ($\Omega$) Balancing Length $l$ ($cm$) $(100 - l)$ ($cm$) $X = R(100 - l) / l$ ($\Omega$) Mean $X$ ($\Omega$)
12.040.060.03.003.01 Ω
23.050.050.03.00
34.057.043.03.02
⚠️ Precautions & Sources of Error
  • Jockey must be touched lightly onto wire, never dragged or scraped (scraping distorts wire diameter uniformity).
  • Keep balancing length near $50\text{ cm}$ for maximum bridge sensitivity and minimal percentage error.
💬 Practical Viva-Voce Questions
Q1: Why is the meter bridge most sensitive when the null point is near 50cm?
A: Bridge sensitivity is maximum when all four arms have nearly equal resistance ($P \approx Q \approx R \approx X$). Near 50cm, fractional error $\frac{\Delta X}{X} = \frac{\Delta l}{l} + \frac{\Delta l}{100 - l}$ is mathematically minimized.
EXPERIMENT 12 • Class XII Physics

Wheatstone's Bridge Simulator: 4-Arm Null Balance Network

🎯 Aim of the Experiment

To determine the unknown resistance of a resistor by setting up a 4-arm Wheatstone's bridge network and verifying null condition.

🧰 Apparatus & Materials Required

Wheatstone bridge quadrilateral assembly with ratio arms ($P, Q$), adjustable resistance arm ($R$), unknown arm ($S$), galvanometer, DC battery, key.

📐 Governing Theory & Formulae

In a closed bridge network $ABCD$, when potential at junction $B$ equals potential at junction $D$, no current flows through galvanometer ($I_g = 0$).

$$\frac{P}{Q} = \frac{R}{S} \implies S = R \left(\frac{Q}{P}\right)$$
📝 Step-by-Step Procedure
  1. Set ratio arms $P$ and $Q$ to desired ratio (e.g. $10\,\Omega : 10\,\Omega$ or $100\,\Omega : 10\,\Omega$).
  2. Connect unknown resistor in arm $S$.
  3. Depress battery key $K_1$ first, then tap galvanometer key $K_2$.
  4. Adjust resistance $R$ until galvanometer deflection drops to exactly zero.
  5. Compute unknown resistance $S = R(Q/P)$.
📊 Observation Tables & Sample Readings
Trial Arm $P$ ($\Omega$) Arm $Q$ ($\Omega$) Ratio $Q / P$ Standard $R$ ($\Omega$) Unknown $S$ ($\Omega$)
11001001.015.015.0
210001000.1150.015.0
⚠️ Precautions & Sources of Error
  • Always close battery key first, then galvanometer key to prevent transient inductive deflection kick.
💬 Practical Viva-Voce Questions
Q1: What happens if battery and galvanometer connections are interchanged?
A: The balance condition remains completely unaltered ($\frac{P}{Q} = \frac{R}{S}$ is symmetrical). However, sensitivity may slightly change.
EXPERIMENT 13 • Class XI / XII Physics

Frequency of AC Mains with Sonometer

🎯 Aim of the Experiment

To determine the frequency of alternating current (AC) mains using a sonometer (by observing the resonant vibration of a stretched wire driven by electromagnetic force).

🧰 Apparatus & Materials Required

A sonometer with a non-magnetic wire (brass or copper) or soft iron wire, two sharp knife-edge bridges ($A$ and $B$), a step-down transformer (2V–6V AC), a strong permanent horseshoe magnet (or AC electromagnet), a weight hanger with slotted 500g weights, an inverted V-shaped light paper rider, a screw gauge micrometer, and a meter scale.

📐 Governing Theory & Formulae

The fundamental frequency of transverse standing waves in a stretched wire of length $l$, tension $T = Mg$, and linear mass density $m$ is:

$$\nu_0 = \frac{1}{2l}\sqrt{\frac{T}{m}}$$

Case 1 (Method A: Non-magnetic wire carrying AC in transverse B-field): By Fleming's Left-Hand Rule, the Lorentz force alternates direction once per half cycle of the AC current. Thus, the wire is driven at the AC mains frequency $f$:

$$f = \frac{1}{2l}\sqrt{\frac{T}{m}} \implies \frac{\sqrt{T}}{l} = 2f\sqrt{m} = \text{constant}$$

Case 2 (Method B: Ferromagnetic soft iron wire under an AC electromagnet): The soft iron wire is attracted twice per AC cycle (during both positive and negative half-cycles). Hence, the wire oscillates at $2f$, yielding:

$$2f = \frac{1}{2l}\sqrt{\frac{T}{m}} \implies f = \frac{1}{4l}\sqrt{\frac{T}{m}}$$

The linear mass density of the wire is determined from its radius $r = d/2$ and density $\rho$: $m = \pi r^2 \rho$.

📝 Step-by-Step Procedure
  1. Suspend a known mass $M$ (e.g. 1.0 kg) on the hanger to establish wire tension $T = Mg$.
  2. Position the horseshoe magnet (or electromagnet) at the exact midpoint between bridges $A$ and $B$.
  3. Place a light inverted V paper rider on the wire at the midpoint (fundamental antinode).
  4. Switch on the safe low-voltage AC supply from the step-down transformer.
  5. Gently slide movable Bridge $B$ towards the resonant length. As resonance approaches, the paper rider will flutter vigorously; at exact resonance ($l_0$), the rider is violently thrown off ("flies off!").
  6. Note the resonant length $l_1$ while increasing length and $l_2$ while decreasing length. Record the mean length $l = (l_1 + l_2)/2$.
  7. Repeat for suspended loads $M = 1.0, 1.5, 2.0, 2.5, 3.0\text{ kg}$.
  8. Plot a graph of $\sqrt{T}$ against $l$. The slope of this straight line through the origin equals $2f\sqrt{m}$, from which $f = \frac{\text{Slope}}{2\sqrt{m}}$.
📊 Observation Tables & Sample Readings
S.No. Mass $M$ (kg) Tension $T = Mg$ (N) $\sqrt{T}$ ($\text{N}^{1/2}$) Resonant Length $l$ (cm) $l$ (m) $\frac{\sqrt{T}}{l}$ ($\text{N}^{1/2}/\text{m}$) Frequency $f$ (Hz)
11.09.803.13063.20.6324.9550.1
21.514.703.83477.40.7744.9550.0
32.019.604.42789.40.8944.9550.0
⚠️ Precautions & Sources of Error
  • Ensure the wire is kink-free, uniform in cross-section, and rests firmly on the sharp edges of the knife bridges.
  • Keep the pulley wheel frictionless and well lubricated.
  • Always use safe low-voltage AC (2V–6V) from a step-down transformer to prevent electric shock and avoid wire heating ($I^2Rt$).
  • The paper rider must be placed exactly at the center between the bridges where the antinode occurs.
💬 Practical Viva-Voce Questions
Q1: What is the standard frequency of AC mains in India?
A: 50 Hz (or 50 cycles per second). In the United States, it is 60 Hz.
Q2: Why does the wire vibrate with AC frequency $f$ in a transverse magnetic field?
A: By Fleming's Left-Hand Rule, the magnetic Lorentz force $F = I L \times B$ changes direction every time current reverses sign. One complete AC cycle produces one complete oscillation of mechanical force.
Q3: Why does a soft iron wire vibrate at $2f$ under an AC electromagnet?
A: An electromagnet magnetizes and attracts ferromagnetic soft iron during both the positive and negative peaks of the AC cycle. Thus, attraction occurs twice per cycle ($2f$).
EXPERIMENT 14 • Class XII Physics

Resistance of a Galvanometer by Half-Deflection Method & Figure of Merit

🎯 Aim of the Experiment

To determine the resistance of a moving coil galvanometer by half-deflection method and to find its figure of merit ($k$).

🧰 Apparatus & Materials Required

A Weston-type moving coil galvanometer, a regulated DC power source / 2V accumulator, a high resistance box ($R$, range $1000 - 10000\ \Omega$), a low resistance box ($S$, range $1 - 250\ \Omega$), two one-way plug keys ($K_1$ and $K_2$), connecting wires, and sandpaper.

📐 Governing Theory & Formulae

1. Determination of Galvanometer Resistance ($G$):

When high resistance $R$ is connected in series with the galvanometer across an EMF $E$, closing key $K_1$ with key $K_2$ open yields current:

$$I = \frac{E}{R + G} = k \cdot \theta$$

where $\theta$ is the initial deflection and $k$ is the figure of merit. When shunt resistance $S$ is connected in parallel with the galvanometer by closing key $K_2$, the galvanometer current becomes:

$$I_g = \frac{E \cdot S}{R(G + S) + G \cdot S} = k \cdot \theta'$$

If $S$ is adjusted so that the deflection becomes exactly half ($\theta' = \frac{\theta}{2}$), then:

$$G = \frac{R \cdot S}{R - S}$$

Because $R$ is chosen to be much larger than $S$ ($R \gg S$), $(R - S) \approx R$, leading to $G \approx S$.

2. Figure of Merit ($k$):

The figure of merit $k$ is the current required to produce unit division deflection on the galvanometer scale:

$$k = \frac{E}{(R + G)\theta} \quad \text{(A/div)}$$

The current sensitivity is $S_i = \frac{1}{k}$, and the full-scale deflection current for $n = 30$ divisions is $I_g = n \cdot k$.

📋 Standard Experimental Procedure
  1. Clean the ends of all connecting leads with sandpaper to eliminate contact oxidation.
  2. Connect the battery $E$, high resistance box $R$, key $K_1$, and galvanometer $G$ in series. Connect shunt box $S$ and key $K_2$ in parallel across the galvanometer terminals.
  3. Ensure all plugs in resistance boxes are tightly seated. Initially, leave key $K_2$ open.
  4. Unplug a high resistance (e.g. $4000\ \Omega$ to $6000\ \Omega$) from box $R$, and insert key $K_1$.
  5. Fine-tune $R$ so that the deflection $\theta$ on the galvanometer scale is an even number within the upper readable range (e.g. 26, 28, or 30 divisions). Record $R$ and $\theta$.
  6. Keeping $R$ unchanged, insert plug key $K_2$. The deflection drops due to current bypass through shunt $S$.
  7. Adjust the resistance in shunt box $S$ until the deflection becomes exactly half of $\theta$ ($\theta' = \theta / 2$). Record $S$ and $\theta/2$.
  8. Repeat the procedure for at least 4 to 5 different values of $R$ and initial deflection $\theta$.
  9. Calculate $G = \frac{R \cdot S}{R - S}$ and $k = \frac{E}{(R + G)\theta}$ for each set and determine mean values.
📊 Observation Table

EMF of Cell $E = 2.00\text{ V}$, Total Scale Divisions $n = 30$

S.No. High Resistance $R$ (Ω) Deflection $\theta$ (div) Shunt Resistance $S$ (Ω) Half-Deflection $\theta/2$ (div) Galvanometer Resistance $G = \frac{RS}{R-S}$ (Ω) Figure of Merit $k = \frac{E}{(R+G)\theta}$ (A/div)
1 4500 22 75 11 76.3 1.99 × 10⁻⁵
2 4000 24 75 12 76.4 2.04 × 10⁻⁵
3 3500 28 75 14 76.6 2.00 × 10⁻⁵
4 3200 30 75 15 76.8 2.03 × 10⁻⁵

Mean Galvanometer Resistance ($G$): $76.5\ \Omega$ | Mean Figure of Merit ($k$): $2.02 \times 10^{-5}\text{ A/div}$

⚠️ Precautions & Sources of Error
  • Always unplug high resistance in $R$ before inserting key $K_1$ to protect the delicate suspension and pointer of the galvanometer.
  • Plugs in both resistance boxes must be firmly turned to minimize contact resistance.
  • The EMF of the battery must remain constant throughout the run; avoid leaving $K_1$ closed continuously.
  • The deflection $\theta$ should preferably be an even number so that dividing by 2 yields an exact whole scale division.
💬 Viva-Voce Questions & Answers
Q1: What is a moving coil galvanometer and upon what principle does it function?
A: It is an instrument used to detect very small electric currents. It functions on the principle that a current-carrying coil suspended in a uniform radial magnetic field experiences a deflecting magnetic torque: $\tau = N I A B$, which is counterbalanced by restoring torque of a phosphor-bronze spring: $\tau = C \theta$.
Q2: Why is the scale of a moving coil galvanometer linear?
A: Cylindrical pole pieces and a soft iron core create a uniform radial magnetic field where the plane of the coil remains parallel to magnetic field lines at all angles ($\sin\theta = 1$). Hence, deflecting torque is directly proportional to current ($\theta \propto I$).
Q3: Why must resistance $R$ be much greater than shunt $S$?
A: When $R \gg S$, the total circuit resistance changes negligibly upon connecting $S$ in parallel with $G$. This ensures the total current drawn from the cell remains practically constant, validating $G = \frac{RS}{R-S} \approx S$.
EXPERIMENT 15 • Class XII Physics

Conversion of Galvanometer into a Voltmeter of Desired Range & Verification

🎯 Aim of the Experiment

To convert the given galvanometer (of known resistance $G$ and figure of merit $k$) into a voltmeter of desired range (say $0 - 3\text{ V}$) and to verify the same with a standard voltmeter.

🧰 Apparatus & Materials Required

A moving coil galvanometer of known resistance $G$ and figure of merit $k$, a standard calibrated DC voltmeter ($0 - 3\text{ V}$), a high resistance box / multiplier resistor $R$, a DC battery / accumulator (4V), a wire-wound rheostat configured as a potential divider, a plug key, and connecting wires.

📐 Governing Theory & Formulae

A moving coil galvanometer is converted into a voltmeter by connecting a calculated high multiplier resistance $R$ in series with it.

1. Full-scale deflection current:

$$I_g = n \cdot k$$

where $n$ is the total scale divisions ($n = 30$) and $k$ is the figure of merit.

2. Series multiplier resistance $R$ for target range $V$:

$$R = \frac{V}{I_g} - G$$

3. Least count and observed voltage:

$$\text{Least Count (LC)} = \frac{V}{n} \implies V_2 = \theta \times \text{LC}$$

4. Verification error:

$$\Delta V = V_2 - V_1$$

where $V_1$ is the reading observed on the standard master voltmeter.

📋 Standard Experimental Procedure
  1. Record the galvanometer parameters: coil resistance $G$ and figure of merit $k$ (determined from Experiment 14), and total scale divisions $n$.
  2. Calculate the full-scale current $I_g = n \cdot k$ and the required series multiplier resistance $R = \frac{V}{I_g} - G$ for the desired voltage range $V$ (e.g. $0 - 3.0\text{ V}$).
  3. Unplug the calculated value of resistance $R$ from the high resistance box and connect it in series with the galvanometer. This combination acts as the converted voltmeter.
  4. Set up the potential divider verification circuit: connect the DC battery across the fixed end terminals of the wire-wound rheostat through a plug key.
  5. Connect the standard voltmeter and the converted galvanometer voltmeter in parallel between one fixed terminal and the movable slider jockey of the rheostat.
  6. Insert the plug key and position the slider jockey near the minimum voltage end.
  7. Gradually advance the jockey so that the standard voltmeter reads $0.5\text{ V}, 1.0\text{ V}, 1.5\text{ V}, \dots$ Record standard voltmeter reading $V_1$ and galvanometer deflection $\theta$.
  8. Compute converted voltage $V_2 = \theta \times \text{LC}$ and determine the discrepancy $\Delta V = V_2 - V_1$.
  9. Plot the calibration error curve: error $\Delta V$ on the vertical axis versus standard voltmeter reading $V_1$ on the horizontal axis.
📊 Observation Table

Range: $0 - 3.0\text{ V}$, $G = 75\ \Omega$, $k = 20\ \mu\text{A/div}$, $I_g = 600\ \mu\text{A}$, Multiplier $R = 4925\ \Omega$, $\text{LC} = 0.1\text{ V/div}$

S.No. Standard Voltmeter Reading $V_1$ (V) Galvanometer Deflection $\theta$ (div) Converted Voltmeter Reading $V_2 = \theta \times \text{LC}$ (V) Error $\Delta V = V_2 - V_1$ (V)
1 0.50 5.0 0.50 0.00
2 1.00 10.1 1.01 +0.01
3 1.50 15.0 1.50 0.00
4 2.00 19.9 1.99 -0.01
5 2.50 25.1 2.51 +0.01
6 3.00 30.0 3.00 0.00

Conclusion: The calculated and observed voltages agree closely with deviations well within permissible calibration limits ($\pm 0.02\text{ V}$).

💬 Viva-Voce Questions & Answers
Q1: Why is a voltmeter connected in parallel with circuit components?
A: Potential difference exists between two points in a circuit. Connecting a voltmeter in parallel allows it to sample this potential difference without interrupting current flow in the branch.
Q2: Why must a voltmeter have very high resistance?
A: If a voltmeter drew significant current, it would lower the effective resistance of the circuit branch and alter the potential difference being measured. A very high resistance ensures negligible current is drawn.
Q3: How is a galvanometer converted into an ammeter instead of a voltmeter?
A: To convert into an ammeter, a very low resistance (shunt $S = \frac{I_g \cdot G}{I - I_g}$) is connected in parallel with the galvanometer, allowing large current to bypass the coil.
EXPERIMENT 16 • CLASS XII • RAY OPTICS

Focal Length of Concave Mirror by u–v Method

🚀 Launch Simulator
🎯 Aim of the Experiment

To find the value of $v$ for different values of $u$ in case of a concave mirror and to find its focal length ($f$).

📐 Apparatus & Principle

Apparatus: Optical bench with four uprights, concave mirror with holder, two optical pins (object pin and image pin), knitting needle (for index correction), spirit level.

$$\frac{1}{f} = \frac{1}{v} + \frac{1}{u} \implies f = \frac{u \cdot v}{u + v}$$ $$\text{Where } u = \text{distance of object pin from mirror pole, } v = \text{distance of image pin from mirror pole.}$$
🔬 Step-by-Step Procedure
  1. Level the optical bench with a spirit level and mount the concave mirror in a holder at one end.
  2. Determine rough focal length ($f_{\text{rough}}$) by focusing a distant tree or building on a white card.
  3. Place the object needle at a distance greater than $f$ (between $f$ and $2f$, or beyond $2f$).
  4. Observe the inverted real image of the object pin. Move the image pin along the bench until its tip coincides with the inverted tip of the image.
  5. Remove parallax between the image pin tip and image tip by shifting the eye laterally.
  6. Record the positions of mirror, object pin, and image pin. Repeat for at least 5 different values of $u$.
📊 Observation Table
Obs # Mirror Pos (cm) Object Pin $u$ (cm) Image Pin $v$ (cm) Focal Length $f = \frac{uv}{u+v}$ (cm)
10.035.030.016.15
20.032.032.016.00
30.030.034.316.01
40.028.037.316.00
50.026.041.616.00

Result: Mean focal length of concave mirror $f = 16.03\text{ cm}$.

💬 Viva-Voce Questions & Answers
Q1: What is optical parallax?
A: Parallax is the apparent relative displacement between two objects when viewed from two different vantage points due to separation along the line of sight.
Q2: How do you determine whether the image needle is in front or behind the image?
A: The object closer to the eye moves in the direction opposite to the eye shift; the object farther away moves in the same direction as the eye shift.
EXPERIMENT 17 • CLASS XII • RAY OPTICS

Focal Length of Convex Mirror Using Auxiliary Convex Lens

🚀 Launch Simulator
🎯 Aim of the Experiment

To find the focal length of a convex mirror, using an auxiliary convex lens.

📐 Principle & Formula

A convex mirror forms a virtual image for a real object. By placing an auxiliary convex lens, a real converging beam is formed. When the convex mirror is placed in the path, rays falling normally reflect back along their paths if the center of curvature $C$ coincides with the point $I$ where rays would have focused.

$$R = I - M, \quad f = \frac{R}{2} = \frac{I - M}{2}$$ $$\text{Where } M = \text{position of convex mirror, } I = \text{position of image without mirror.}$$
📊 Observation Table
Obs # Lens Pos (cm) Image Pos without Mirror $I$ (cm) Mirror Pos $M$ (cm) Radius $R = I - M$ (cm) Focal Length $f = R/2$ (cm)
140.075.055.020.010.00
240.075.054.920.110.05
342.077.057.020.010.00

Result: Mean focal length of convex mirror $f = 10.02\text{ cm}$.

💬 Viva-Voce Questions
Q1: Why is an auxiliary convex lens required?
A: A convex mirror always diverges incident rays from a real object and forms an inaccessible virtual image behind itself. The auxiliary lens produces a converging beam acting as a virtual object.
EXPERIMENT 18 • CLASS XII • RAY OPTICS

Focal Length of Convex Lens (u–v Graphs)

🚀 Launch Simulator
🎯 Aim of the Experiment

To find the focal length of a convex lens by plotting graphs between $u$ and $v$ or between $1/u$ and $1/v$.

📐 Working Formula
$$\frac{1}{f} = \frac{1}{v} - \frac{1}{u} \implies f = \frac{u \cdot v}{u + v} \quad \text{(with sign convention: } u < 0, v > 0\text{)}$$ $$\text{From } \frac{1}{u}\text{ vs }\frac{1}{v}\text{ graph: } \frac{1}{f} = \text{intercept on either axis.}$$
📊 Observation Table
Obs # $u$ (cm) $v$ (cm) $1/u$ ($\text{cm}^{-1}$) $1/v$ ($\text{cm}^{-1}$) $f = \frac{uv}{u+v}$ (cm)
125.037.50.04000.026715.00
230.030.00.03330.033315.00
335.026.250.02860.038115.00
440.024.00.02500.041715.00

Result: Mean focal length of convex lens $f = 15.00\text{ cm}$; Optical Power $P = +6.67\text{ D}$.

EXPERIMENT 19 • CLASS XII • RAY OPTICS

Focal Length of Concave Lens Using Auxiliary Convex Lens

🚀 Launch Simulator
🎯 Aim of the Experiment

To find the focal length of a concave lens, using an auxiliary convex lens.

📐 Working Formula
$$\frac{1}{f} = \frac{1}{v} - \frac{1}{u} \implies f = \frac{u \cdot v}{u - v}$$ $$\text{Where } u = I_1 - L_2 \text{ (virtual object distance), } v = I_2 - L_2 \text{ (real image distance).}$$
📊 Observation Table
Obs # $L_1$ Pos (cm) $I_1$ Pos (cm) $L_2$ Pos (cm) $I_2$ Pos (cm) $u = I_1 - L_2$ $v = I_2 - L_2$ $f = \frac{uv}{u-v}$ (cm)
130.060.048.072.0+12.0+24.0-24.00
230.060.046.081.0+14.0+35.0-23.33
330.060.050.066.7+10.0+16.7-24.92

Result: Mean focal length of concave lens $f = -24.08\text{ cm}$.

EXPERIMENT 20 • CLASS XII • RAY OPTICS

Angle of Minimum Deviation for a Prism (i–δ Graph)

🚀 Launch Simulator
🎯 Aim of the Experiment

To determine angle of minimum deviation for a given prism by plotting a graph between angle of incidence and angle of deviation.

📐 Governing Formulas
$$\delta = i + e - A$$ $$\mu = \frac{\sin\left(\frac{A + D_m}{2}\right)}{\sin\left(\frac{A}{2}\right)}$$ $$\text{For equilateral prism, } A = 60^\circ, \quad \mu = \frac{\sin(30^\circ + D_m/2)}{\sin 30^\circ}$$
📊 Observation Table
Obs # Angle of Incidence $i$ (deg) Angle of Emergence $e$ (deg) Angle of Deviation $\delta = i+e-A$ (deg)
135.0°70.2°45.2°
240.0°58.8°38.8°
345.0°52.3°37.3°
448.6°48.6°37.2° (Minimum Dm)
555.0°43.8°38.8°
660.0°41.2°41.2°

Result: Minimum deviation $D_m = 37.2^\circ$; Refractive index $\mu = 1.500$.

EXPERIMENT 21 • CLASS XII • OPTICAL INSTRUMENTS

Refractive Index of Glass Slab Using Travelling Microscope

🚀 Launch Simulator
🎯 Aim of the Experiment

To determine refractive index of a glass slab using a travelling microscope.

📐 Working Formula & Least Count
$$\mu = \frac{\text{Real Depth}}{\text{Apparent Depth}} = \frac{R_3 - R_1}{R_3 - R_2}$$ $$\text{Least Count (LC)} = \frac{1\text{ MSD}}{50} = \frac{0.05\text{ cm}}{50} = 0.001\text{ cm}$$
📊 Observation Table
Obs # $R_1$ Paper Mark (cm) $R_2$ Apparent Mark (cm) $R_3$ Top Dust (cm) Real Depth $R_3-R_1$ (cm) Apparent Depth $R_3-R_2$ (cm) $\mu = \frac{R_3-R_1}{R_3-R_2}$
12.0002.6003.8001.8001.2001.500
22.1002.7013.9001.8001.1991.501
32.2002.8024.0001.8001.1981.502

Result: Mean refractive index of glass slab $\mu = 1.501$.

EXPERIMENT 22 • CLASS XII • RAY OPTICS

Refractive Index of Liquid (Liquid Lens Method)

🚀 Launch Simulator
🎯 Aim of the Experiment

To find the refractive index of a liquid using convex lens and plane mirror.

📐 Working Formulas
$$\frac{1}{f_2} = \frac{1}{F} - \frac{1}{f_1} \implies f_2 = \frac{f_1 \cdot F}{f_1 - F}$$ $$\mu = 1 - \frac{R}{f_2} = 1 + \frac{R}{|f_2|}$$
📊 Observation Table
Obs # Liquid $f_1$ Dry Lens (cm) $F$ Combination (cm) $f_2$ Liquid Lens (cm) $R$ (cm) $\mu = 1 - R/f_2$
1Water20.030.0-60.020.01.333
2Glycerine20.038.2-42.020.01.476
3Castor Oil20.038.5-41.620.01.481

Result: Refractive index of water $\mu_w = 1.333$; Glycerine $\mu_g = 1.476$.

EXPERIMENT 23 • CLASS XII • RAY OPTICS

Refractive Index of Liquid Using Concave Mirror & Plane Mirror

🚀 Launch Simulator
🎯 Aim of the Experiment

To find the refractive index of a liquid using a concave mirror and a plane mirror.

📐 Working Formula
$$\mu = \frac{h_1 - h_0}{h_2 - h_0}$$ $$\text{Where: } h_1 = \text{height of needle tip above dry concave mirror at } C \ (h_1 = R),$$ $$h_0 = \text{height of plane mirror strip resting on liquid surface from pole,}$$ $$h_2 = \text{height of needle tip when coincident with image through liquid-mirror combination.}$$ $$\text{For a thin layer of liquid } (h_0 \approx 0): \quad \mu \approx \frac{h_1}{h_2}$$
📊 Observation Table
Obs # Liquid $h_1$ Dry Mirror (cm) $h_0$ Strip Surface (cm) $h_2$ Liquid Coincidence (cm) $\mu = \frac{h_1 - h_0}{h_2 - h_0}$
1Water30.01.022.81.330
2Glycerine30.01.020.71.472
3Castor Oil30.01.020.61.480

Result: Refractive index of water $\mu_w = 1.330$; Glycerine $\mu_g = 1.472$; Castor Oil $\mu_c = 1.480$.

💬 Viva-Voce Questions
Q1: Why is the needle placed at the center of curvature $C$ of the concave mirror?
A: Rays originating from the center of curvature strike the spherical mirror normally along its radii and retrace their path, forming an inverted real image of the same size at $C$ with zero parallax.
Q2: Why does the apparent center of curvature move closer when liquid is poured into the mirror?
A: Refraction at the flat upper surface of the liquid bends the rays toward the normal as they enter the denser medium, making the center of curvature appear closer to the surface by a factor of $\mu$.
Q3: What is the purpose of placing a plane mirror strip on the liquid surface?
A: It establishes a direct reference for the height $h_0$ of the upper liquid surface from the mirror pole, allowing precise calculation via $\mu = \frac{h_1 - h_0}{h_2 - h_0}$.
EXPERIMENT 24 • CLASS XII • SEMICONDUCTOR ELECTRONICS

P-N Junction Diode I–V Characteristics

🚀 Launch Simulator
🎯 Aim of the Experiment

To draw the $I-V$ characteristic curve for a p-n junction diode in forward and reverse bias.

📐 Principle & Dynamic Resistance
$$r_{\text{dynamic}} = \frac{\Delta V}{\Delta I}$$ $$\text{Forward dynamic resistance } r_f = \frac{\Delta V_F}{\Delta I_F} \quad (\sim 10-50\ \Omega)$$ $$\text{Reverse dynamic resistance } r_r = \frac{\Delta V_R}{\Delta I_R} \quad (\sim \text{Mega-ohms})$$
📊 Observation Tables

Forward Bias

$V_F$ (V)$I_F$ (mA)
0.200.02
0.400.10
0.600.42
0.701.25
0.8010.5
0.9028.0

Reverse Bias

$V_R$ (V)$I_R$ (μA)
5.01.2
10.01.4
20.01.8
30.02.5
35.018.5

Result: Silicon diode knee voltage $V_k \approx 0.70\text{ V}$; Breakdown voltage $V_z \approx 35\text{ V}$; Forward dynamic resistance $r_f \approx 18.2\ \Omega$.

💬 Viva-Voce Questions
Q1: What is knee voltage?
A: The forward bias voltage at which diode current begins to increase exponentially ($0.7\text{ V}$ for Si, $0.3\text{ V}$ for Ge).
Q2: Why is reverse current measured in microamperes while forward in milliamperes?
A: Forward current is carried by majority carriers (high density), whereas reverse saturation current is carried solely by thermally generated minority carriers (very low density).