SMA Physics • Class XI Physics

Weight of a Body: Parallelogram Law of Vectors

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Gravesand's Board: Pulleys, Knot & Optical Alignment Pins Equilibrium Achieved
Parallelogram Construction: Collinear Vectors $\vec{P}, \vec{Q}$ and Resultant $\vec{R}$ Included Angle θ = 0.0°
Tension $P$
60 g.wt
Tension $Q$
60 g.wt
Resultant $R$
0.0 g.wt
Actual $W$
75.0 g.wt
Unknown Suspended Body ($W$)
Left Arm Slotted Weights ($P$) 60 g.wt
Right Arm Slotted Weights ($Q$) 60 g.wt
Observation Table
# Body $P$ (g.wt) $Q$ (g.wt) $\theta$ (°) Resultant $R$ Error %
No records logged yet. Establish equilibrium and log.
Parallelogram Law Equation: R = √(P² + Q² + 2PQ cos θ)
Evaluated Weight $W$: -- g.wt Error: 0.0%